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9x^2+30x=72
We move all terms to the left:
9x^2+30x-(72)=0
a = 9; b = 30; c = -72;
Δ = b2-4ac
Δ = 302-4·9·(-72)
Δ = 3492
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3492}=\sqrt{36*97}=\sqrt{36}*\sqrt{97}=6\sqrt{97}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-6\sqrt{97}}{2*9}=\frac{-30-6\sqrt{97}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+6\sqrt{97}}{2*9}=\frac{-30+6\sqrt{97}}{18} $
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